Medium
Given an unsorted array of integers nums
, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n)
time.
Example 1:
Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]
. Therefore its length is 4.
Example 2:
Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9
Constraints:
0 <= nums.length <= 105
-109 <= nums[i] <= 109
public class Solution {
public int LongestConsecutive(int[] nums) {
Dictionary<int, int> mapToHighest = new(nums.Length);
int best = 0;
for (int i = 0; i < nums.Length; i++) {
int rangeLow = 0;
int rangeHigh = 0;
if (mapToHighest.ContainsKey(nums[i])) {
continue;
}
if (mapToHighest.TryGetValue(nums[i]-1, out var downCount)) {
rangeLow = downCount;
}
if (mapToHighest.TryGetValue(nums[i]+1, out var upCount)) {
rangeHigh = upCount;
}
int thisSum = rangeLow + rangeHigh + 1;
mapToHighest[nums[i] - rangeLow] = thisSum;
mapToHighest[nums[i] + rangeHigh] = thisSum;
if (rangeLow != 0 && rangeHigh != 0) {
mapToHighest[nums[i]] = 1;
}
best = Math.Max(thisSum, best);
}
return best;
}
}