Easy
Given a pattern
and a string s
, find if s
follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in pattern
and a non-empty word in s
.
Example 1:
Input: pattern = “abba”, s = “dog cat cat dog”
Output: true
Example 2:
Input: pattern = “abba”, s = “dog cat cat fish”
Output: false
Example 3:
Input: pattern = “aaaa”, s = “dog cat cat dog”
Output: false
Example 4:
Input: pattern = “abba”, s = “dog dog dog dog”
Output: false
Constraints:
1 <= pattern.length <= 300
pattern
contains only lower-case English letters.1 <= s.length <= 3000
s
contains only lower-case English letters and spaces ' '
.s
does not contain any leading or trailing spaces.s
are separated by a single space.public class Solution {
public bool WordPattern(string pattern, string s) {
Dictionary<char, string> dict = new();
string[] str = s.Split(" ");
if (pattern.Length != str.Length) {
return false;
}
for (int i = 0; i < pattern.Length; i++) {
if (!dict.ContainsKey(pattern[i]) && !dict.ContainsValue(str[i])) {
dict.Add(pattern[i], str[i]);
}
if (!dict.ContainsKey(pattern[i]) || !str[i].Equals(dict[pattern[i]])) {
return false;
}
}
return true;
}
}